What element is CH3O?

What element is CH3O?

The chemical name for CH3O is methoxide. It is a base formed from methanol by replacement of the hydroxyl hydrogen with a metal. A strong base and a good nucleophile. Methoxide contains one atom of carbon, three atoms of hydrogen and one atom of oxygen.

What functional group is CH3O?

It is a volatile compound which means that it is easily vaporized at room temperature. It is the simplest alcohol that consists of a methyl group and a hydroxyl group.

Why is CH3O a strong base?

CH3O- is a stronger base than CH3NH2 mostly because of the negative charge on CH3O-, which leads to greater attraction to all things positive, including H+.

Why is Methoxide a stronger base than hydroxide?

Alkoxides tend to be stronger bases than the hydroxide ion. Adjacent atoms in an alkane chain will donate electron density to oxygen, allowing it to be more polarizable. So one would expect methoxide to be a better nucleophile than hydroxide because it is a stronger base than hydroxide and still remains unhindered.

Which is better Nucleophile OH or CH3O?

1)ch3 is +I so ch3o- is better nucleophile. 2)ch3oh is stronger acid, oh- is stronger base, stronger nucleophile.

How do you know if you’re ortho or para?

If the relative yield of the ortho product and that of the para product are higher than that of the meta product, the substituent on the benzene ring in the monosubstituted benzene is called an ortho, para directing group. If the opposite is observed, the substituent is called a meta directing group.

Is OCH3 an activator or deactivator?

Methoxy group (och3) is an electron-withdrawing group and hence is it is a deactivator.

Is OCH3 an electrophile?

Both are EDG, OCH3 is more than CH3 due to the presence of lone pairs of electrons on oxygen. OCH3 group have +M effect by resonance, but CH3 group have +I effect and hyper conjugation. Again OCH3 group attached to the benzene to promote Ortho Para substitution in EAS, electrophilic substitution in Aromatic system.

Is methoxy EWG or EDG?

Since σp < 0, the para-methoxy substituent is an EDG (even though the same group is an EWG in the meta position). Comparing the σ values for meta and para, we can see that the electron donating resonance effects (σR) dominate over the electron withdrawing inductive effect (σI).