Is x2 12x 36 a perfect square?
Is x2 12x 36 a perfect square?
x2 + 12x + 36 is called a perfect square trinomial — which is the square of a binomial.
Why can’t a sum of squares be factored?
It’s true that you can’t factor A²+B² on the reals — meaning, with real-number coefficients — if A and B are just simple variables. So it’s still true that a sum of squares can’t be factored as a sum of squares on the reals.
Is the sum of two perfect squares always prime?
Hence, the answer is No, because the numbers (perfect squares) that you added is not only divisible by one and itself.
Which is the sum of two cubes?
The sum or difference of two cubes can be factored into a product of a binomial times a trinomial. That is, x3+y3=(x+y)(x2−xy+y2) and x3−y3=(x−y)(x2+xy+y2) .
What is A /( B C?
a/(b/c) = ac/b. Just a note that you have to be careful. The above is only true when both b and c are not 0. The reason is that division by 0 is undefined. In the above proof (c/c) is used which is 0/0 when c=0.
How do you find a 3 b 3?
What is the formula for (a3 – b3)?
- Answer: (a3 – b3) = (a – b)(a2 + b2 + ab) Let us prove this by considering a = 4 and b= 2 then. (43 – 23) = (4 – 2)(42 + 22 + 4 × 2)
- LHS = 56. RHS = (a – b)(a2 + b2 + ab) RHS = (4 – 2)(42 + 22 + 4 × 2)
- RHS = 56. ∴ LHS = RHS. (a3 – b3) = (a – b)(a2 + b2 + ab) Hence the proof.
What is the formula of a4 b4?
= a^4 + 2a^2b^2 + b^4.
What is the formula of 4 B 4?
Given, a4−b4=(a2)2−(b2)2=(a2+b2)(a2−b2)(∵x2−y2=(x+y)(x−y))=(a2+b2)(a+b)(a−b)
What is the formula of a 3 B 3 C 3 3abc?
(a3 + b3 + c3 – 3abc) = (a + b + c)*(a2 + b2 + c2 – ab – bc – ac) 13.
How do you prove a3 b3 c3 3abc?
a3+b3+c3-3abc =(a+b+c)(a2+b2+c2-ab-bc-ac) by taking LHS.
What is the value of a 3 b 3 c 3?
a3 + b3 + c3 – 3abc = (a + b + c)(a2 + b2 + c2 – ab – bc – ca) How is this identity obtained? Let’s see how. Following are a few applications to this identity.
What is the value of 3abc BC A?
Answer: The value of the algebraic expression is 82 provided that , , and .
How do you evaluate an algebraic expression?
To evaluate an algebraic expression, you have to substitute a number for each variable and perform the arithmetic operations. In the example above, the variable x is equal to 6 since 6 + 6 = 12. If we know the value of our variables, we can replace the variables with their values and then evaluate the expression.